Bablosoft

How to process next line from resource file in one script run?

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  • C

    I made a commenting bot for one site, but before comment i must login (saving and restoring cookies doesn't work so for every comment i must log in, solve recaptcha to confirm login and then comment). So i would like to login once and then process all links from text file one by one in just one script run to avoid recaptcha solving many times. How to do that?

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  • S

    Chromium not Running

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    5 Posts
    708 Views
    m4zuperM

    @stevenjpotter57
    Make sure your problem is not caused by your antivirus, Windows Defender, etc.
    If the problem remains relevant, please attach a test project.

  • F

    Why BASPremium I can't hide and show resources or group resources, please tell me

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    1 Posts
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    No one has replied
  • G

    Parse new line to list?

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    4 Posts
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    GaGG

    @gudolik said in Parse new line to list?:

    @GaG Thanks for the idea, but i will have like 50 variables, its bit hassle to save 50 files then read every one one by one, my idea was to parse them into list with command then merge them into 1 list and remove duplicates, i'm not clear with "OnAplicationStart" but will dig videos about it to understand it better

    According to your previous description I thought that you already have that
    variable with 50 or so lines, like on your picture. But if you obtain them 1 by 1
    than it is easy to put them in the list variable 1by 1. Just use "List" module - create
    new empty list firstly, than simply add elements with apropriate "Add list element"
    command. Usually you will be getting elements in some kind of the loop, so
    create empty list before that loop, and inside the loop you can add elements
    (variable - site address) to that new lycreated list variable which is outside the
    loop, so it will hold all elements as a list variable, so no need for any conversions.

  • R

    Running on linux

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    2 Posts
    1003 Views
    ?

    @robotxt no, is not possible

  • N

    Picking randon line from a file/url?

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    2 Posts
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    T

    Select "Mix Lines" in the resource, that way all the lines are mixed and thus it will have a random line. Or you can use javascript to mix the array list using function shuffle to get a better constant randomization. I believe there's also the option "Shuffle List" under the "List" option