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help me! cuts the first character of the string. I get number phone on bass 0338050802. and I want to cut the 0.
If string [[0338050802]] .split ("1")
the result will be =338582. and I want it to be 338050802.
Please help me
@taduy1, this requires using slice(), not split().
Execute code:
[[NEW_STR]] = [[STR]].slice(1)
[[STR]] - Variable with a string to be shorten [[NEW_STR]] - Variable with string after shortening
[[STR]]
[[NEW_STR]]
[[TEST-STRING]] == [[TEST-STRING]].substring(0)
453973053_1445851109438283_2607446749820192281_n.png I found this after I had you guys help. Thank a lot!
I figured it out nvm. I just set this "\w{32}" as the regex but I actually clicked on the w/ button and then typed in the 32. Seems to work fine
Hello Sorry to waste your precious time. As i always said, im just an old retarded man. I just discovered now on "String" function that i can use the Clean to solve my problem. Thanks anyway
@GhostZ Many many thanks Friend this solve the issue. Thanks again.
@helmish 0_1550789870564_e.txt